Solve the Following Quadratic Equations by Factorization: 4x2 + 4bx - (A2 - B2) = 0 - Mathematics
Solve the following quadratic equations by factorization:
4x 2 + 4bx - (a 2 - b 2 ) = 0

Solution Show Solution
4x2 + 2(a + b)x - 2(a - b)x - (a2 - b2) = 0
2x(2x + a + b) - (a - b)(2x + a + b) = 0
(2x - (a - b))(2x + a + b) = 0
2x - (a - b) = 0
`x=(a-b)/2`
2x + a + b = 0
2x = -(a + b)
`x=(-(a+b))/2`
Hence, `x=(a-b)/2` or `x=(-(a+b))/2`
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Solve the following quadratic equation for x: 4 x 2 + 4 b x − ( a 2 − b 2 ) = 0
The given equation is 4 x 2 + 4 b x − ( a 2 − b 2 ) = 0 ....(i) comparing equation (i) with quadratic equation a x 2 + b x + c = 0 , we get a = 4 , b = 4 b , c = − ( a 2 − b 2 ) by quadratic formula x = − b ± √ b 2 − 4 a c 2 a x = − 4 b ± √ 16 b 2 + 4 × 4 × ( a 2 − b 2 ) 2 × 4 x = − 4 b ± √ 16 b 2 + 16 a 2 − 16 b 2 8 x = − 4 b ± 4 a 8 x = − b ± a 2 therefore, x = − b − a 2 ⇒ − ( a + b 2 ) or x = − b + a 2 ⇒ a − b 2 hence, x = − ( a + b 2 ) and x = a − b 2 ..

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Solve for x : 4x^2 + 4bx - (a^2 - b^2) = 0
Solve for x : 4x 2 + 4bx - (a 2 - b 2 ) = 0
- quadratic equations
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We have, A = 4, B = 4b and C = b 2 - a 2
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