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Problem Solving

This section of the nzmaths website has problem-solving lessons that you can use in your maths programme. The lessons provide coverage of Levels 1 to 6 of The New Zealand Curriculum. The lessons are organised by level and curriculum strand.  Accompanying each lesson is a copymaster of the problem in English and in Māori. 

Choose a problem that involves your students in applying current learning. Remember that the context of most problems can be adapted to suit your students and your current class inquiry. Customise the problems for your class.

The site also includes Problem Solving Information . This provides you with practical information about how to implement problem solving in your maths programme as well as some of the philosophical ideas behind problem solving. We also have a collection of problems and solutions for students to use independently.

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Math Questions Answers

In math questions answers each questions are solved with explanation. The questions are based from different topics. Care has been taken to solve the questions in such a way that students can understand each and every step.

1. Which is greater than 4? (a) 5, (b) -5, (c) -1/2, (d) -25. Solution: 5 greater than 4. Answer: (a)

2. Which is the smallest? (a) -1, (b) -1/2, (c) 0, (d) 3. Solution: The smallest number is -1. Answer: (a) 3. Combine terms: 12a + 26b -4b – 16a. (a) 4a + 22b, (b) -28a + 30b, (c) -4a + 22b, (d) 28a + 30b. Solution: 12a + 26b -4b – 16a. = 12a – 16a + 26b – 4b. = -4a + 22b. Answer: (c) 4. Simplify: (4 – 5) – (13 – 18 + 2). (a) -1, (b) –2, (c) 1, (d) 2. Solution: (4 – 5) – (13 – 18 + 2). = -1-(13+2-18). = -1-(15-18). = -1-(-3). = -1+3. = 2. Answer: (d) 5. What is |-26|? (a) -26, (b) 26, (c) 0, (d) 1 Solution: |-26| = 26. Answer: (b)

Solution: 3y(x – 3) -2(x – 3). = (x – 3)(3y – 2). Answer: (c). 9. Solve for x: 2x – y = (3/4)x + 6. (a) (y + 6)/5, (b) 4(y + 6)/5, (c) (y + 6), (d) 4(y - 6)/5. Solution: 2x – y = (3/4)x + 6. or, 2x - (3/4)x = y + 6. or, (8x -3x)/4 = y + 6. or, 5x/4 = y + 6. or, 5x = 4(y + 6). or, 5x = 4y + 24. or, x = (4y + 24)/5. Therefore, x = 4(y + 6)/5. Answer: (b).

11. Find the value of 3 + 2 • (8 – 3) (a) 25, (b) 13, (c) 17, (d) 24, (e) 15. Solution: 3 + 2 • (8 – 3) = 3 + 2 (5) = 3 + 2 × 5 = 3 + 10 = 13 Answer: (d)

15. What is the radius of a circle that has a circumference of 3.14 meters? Solution: Circumference of a circle = 2πr. Given, circumference = 3.14 meters. Therefore, 2πr = Circumference of a circle or, 2πr = 3.14. or, 2 × 3.14r = 3.14,[Putting the value of pi (π) = 3.14]. or, 6.28r = 3.14. or, r = 3.14/6.28. or, r = 0.5. Answer: 0.5 meter. If students have any queries regarding the questions given in the math questions answers, please fill-up the below comment box to convey your message, so that we can help you.

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